180=62*x^2/3

Solution for 180=62*x^2/3 equation:

180=62x^2/3

We move all terms to the left:

180-(62x^2/3)=0

We get rid of parentheses

-62x^2/3+180=0

We multiply all the terms by the denominator


-62x^2+180*3=0

We add all the numbers together, and all the variables

-62x^2+540=0

a = -62; b = 0; c = +540;
Δ = b2-4ac
Δ = 02-4·(-62)·540
Δ = 133920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{133920}=\sqrt{144*930}=\sqrt{144}*\sqrt{930}=12\sqrt{930}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{930}}{2*-62}=\frac{0-12\sqrt{930}}{-124}
=-\frac{12\sqrt{930}}{-124}
=-\frac{3\sqrt{930}}{-31}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{930}}{2*-62}=\frac{0+12\sqrt{930}}{-124}
=\frac{12\sqrt{930}}{-124}
=\frac{3\sqrt{930}}{-31}
$